The Maximum Sum of 3 Non-Overlapping Subarrays problem asks you to find three contiguous subarrays, each of a fixed length k, such that they do not overlap and their total sum is maximized. You need to return the starting indices of these three subarrays. For example, if you have an array and k=2, you are looking for three distinct blocks of two elements that together give you the biggest possible value.
This "Maximum Sum of 3 Non-Overlapping Subarrays interview question" is a classic "Hard" problem found in Meta, Microsoft, and Google interviews. It tests a candidate's ability to break down a complex global optimization problem into smaller, manageable parts using dynamic programming or pre-computation. It evaluates how well you can handle multiple dependencies and maintain optimal "left" and "right" states while iterating through the middle possibilities.
The "Array, Sliding Window, Dynamic Programming, Prefix Sum interview pattern" involves several steps:
k.left array where left[i] is the index of the best subarray of length k in the range [0, i].right array where right[i] is the index of the best subarray of length k in the range [i, end].j. The total sum is then sum(left_block) + sum(middle_block) + sum(right_block). We track the maximum of this total sum.Array: [1, 2, 1, 2, 6, 7, 5, 1], k = 2.
One frequent error in the "Maximum Sum of 3 Non-Overlapping Subarrays coding problem" is having "off-by-one" errors in the indexing, especially since we have to ensure there is enough space for three subarrays of length k. Another mistake is failing to store the index of the best subarray in the pre-computed left and right arrays, returning only the sum instead. If multiple sets of indices give the same maximum sum, the problem usually requires the lexicographically smallest set, which must be handled with careful comparison logic.
Practice the concept of "splitting the problem at the middle." This technique of pre-calculating optimal values from the left and right side is a standard way to solve many problems involving three parts or two parts with a gap. Once you master this "Left-Middle-Right" strategy, you'll find that many complex-looking array problems become much more approachable.